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set_1 = {1, 2, 3}
#
print("my_set:", set_1)

set_2 = {4, 5, 6}
set_2.discard(10)
print("my_set:", set_2)

# Removing Elements from a Set

To remove a specific element from a set, use the `remove()` or `discard()` functions.

<br />

## Removing Elements with remove()

The `remove()` function removes an element specified within its parentheses from the set.

If the specified element is not present in the set, it raises a KeyError.

```python title="Removing an Element using remove()"
my_set = {1, 2, 3, 4}
my_set.remove(3)

print("my_set:", my_set)
# {1, 2, 4}
```

<br />

## Removing Elements with discard()

Similarly, `discard()` removes an element specified within its parentheses from the set.

Unlike `remove()`, `discard()` does not raise an error if the specified element is not present in the set.

```python title="Removing an Element using discard()"
my_set = {1, 2, 3, 4}
my_set.discard(3)

print("my_set:", my_set) 
# {1, 2, 4}

my_set.discard(5)
# 5 is not in the set, so the operation is executed without any error
```

<br />

## Handling Exceptions with remove()

You can handle exceptions raised by the `remove()` function using a `try-except` block as shown below.

```python title="Handling Exceptions using remove()"
my_set = {1, 2, 3, 4}

try:
    my_set.remove(6)
    # Raises KeyError since 6 is not in the set
except KeyError:
    print("The element does not exist in the set.")
```

The discard() function removes an element from a set without raising an error if the element is not found. In contrast, the remove() function raises a KeyError if the element is not present.

Removing Elements from a Set

Removing Elements with remove()

Removing Elements with discard()

Handling Exceptions with remove()

Which function does not raise an error when trying to remove an element that is not present in a Python set?